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Commit 24d733f2 authored by svornost's avatar svornost
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Add cycle detection to inbreeding calculation.

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1 merge request!7313Add cycle detection to inbreeding calculation.
......@@ -182,30 +182,30 @@ globalThis.ibc = (() => {
return n._coeff;
};
// Populate the NodeCodes.
// Populate the NodeCodes.
//
// Each node has a set of NodeCodes, which represent the set of paths from it to its ancestors.
// NodeCodes here are represented by arrays of integers.
//
// NodeCodes are constructed recursively in this fashion:
//
// - Assign each of the founders (nodes with both parents === null) an unique ID, starting from
// 0 and incrementing each time (the order doesn't matter); a founder's set of NodeCodes has
// - Assign each of the founders (nodes with both parents === null) an unique ID, starting from
// 0 and incrementing each time (the order doesn't matter); a founder's set of NodeCodes has
// exactly one NodeCode, which is [ID] (an array containing only their ID)
//
// - For each other node, let M be its child number w.r.t. its mother and N its child number
// w.r.t. its father, i.e. the number of children that the respective parent has had before
// this one (the order is not important to the algorithm, it's arbitrary here for
// - For each other node, let M be its child number w.r.t. its mother and N its child number
// w.r.t. its father, i.e. the number of children that the respective parent has had before
// this one (the order is not important to the algorithm, it's arbitrary here for
// convenience). Its set of NodeCodes is the set of all its mother's NodeCodes with M appended
// and all of its father's NodeCodes with N appended. For example, if its mother has the
// NodeCodes [[2]] and M = 3 and its father has the NodeCodes [[0,1], [3,1]] and N = 1 then
// and all of its father's NodeCodes with N appended. For example, if its mother has the
// NodeCodes [[2]] and M = 3 and its father has the NodeCodes [[0,1], [3,1]] and N = 1 then
// the set of NodeCodes for this node would be
//
//
// [[2, 3], [0, 1, 1], [3, 1, 1]]
//
// We do this iteratively here, looping over the set of all nodes until each has been assigned
// a NodeCode. This requires looping through a number of times equal to the number of
// generations, since as soon as both parents have NodeCodes their children's NodeCodes may be
// a NodeCode. This requires looping through a number of times equal to the number of
// generations, since as soon as both parents have NodeCodes their children's NodeCodes may be
// computed.
let make_nc = nodes => {
// Generate founder NodeCodes
......@@ -221,7 +221,9 @@ globalThis.ibc = (() => {
});
// Generate the rest of the NodeCodes
while (seen.length != total) {
let oldSeenLength = -1;
while (seen.length !== total) {
oldSeenLength = seen.length;
Object.keys(nodes).forEach(s=> {
let n = nodes[s];
if (seen.includes(+s)) // We've already done this
......@@ -232,7 +234,7 @@ globalThis.ibc = (() => {
seen.push(n.id);
// Compute the NodeCodes from its parents
[n.mother, n.father].forEach((a, i) => {
if (a === null || (n.mother === n.father && i == 1)) // Ignore missing parents/repeated
if (a === null || (n.mother === n.father && i === 1)) // Ignore missing parents/repeated
return;
a.nodecodes.forEach(nc => {
......@@ -245,8 +247,14 @@ globalThis.ibc = (() => {
});
// NodeCodes must be sorted; this suffices
n.nodecodes.sort()
n.nodecodes.sort();
});
// check to make sure we're progressing...if not, there's a cycle in the graph
// dump all the nodes participating in or descended from the cycle and let the player figure it out
if (oldSeenLength === seen.length) {
const badSlaveIDs = Object.keys(nodes).filter(s => !seen.includes(+s)).map(k => nodes[k].id);
throw(`Inbreeding calculation: heritance cycle detected. Check slave IDs: ${badSlaveIDs}`);
}
}
// Cache the string NodeCodes
......@@ -261,7 +269,7 @@ globalThis.ibc = (() => {
// Recursively create the nodes we need, moving upwards from the given slave
let create_node_rec = s => {
// Certain parents (e.g. 0, societal elite) are not considered to be related, despite
// Certain parents (e.g. 0, societal elite) are not considered to be related, despite
// having the same ID; convert them to null
let m = or_null(s.mother);
let f = or_null(s.father);
......@@ -269,7 +277,7 @@ globalThis.ibc = (() => {
// Ensure that parent nodes are created
[m, f].forEach(p => {
if (p !== null && !(p in nodes)) { // Not created, we have to do something
if (p === -1) {
if (p === -1) {
create_node_rec(SugarCube.State.variables.PC);
} else {
// Search for a slave state, genePool entry, or missingTable entry
......
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